Calculation Tool
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"Hydraulics" is the study
and understanding of the behavior of liquids
at rest and in motion.
We are concerned with
water, and the following characteristics of
our application:
|
1. |
How much water do we have.
(Pool Capacity)? |
|
2. |
How fast can we safely move
the water.
(Turnover Rate and Water
Velocity)? |
|
3. |
How much resistance will
this water meet while moving
through the system.
(Friction Loss)? |
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4. |
How will we overcome this
resistance.
(Pump/Filter Sizing)? |
Following are step-by-step instructions
to answer these four questions and
ultimately determine the proper size pump or
filter for virtually any installation.
Below
each step is a calculation based on the
following example:
16 ft
by 32 ft rectangular pool
3 ft
to 8 ft deep 2"" suction side return side
plumbing.
Existing 1 HP pump; filter gauge reads
10 PSI (clean).
Pool Capacity
To determine total gallons, we must first
calculate the surface area of the pool in
square feet:
A. Surface Area ____________ ft 2
(surface area)
Surface Area: 16 ft x 32 ft = 512 ft 2
Next, multiply the surface area by the
average depth to determine the
appropriate volume of the pool.
B. Average Depth
(____________ ft + ____________ ft ) 2 =
____________ ft
(depth, shallow end) (depth, deep end)
(average depth)
Average Depth = (3 ft. + 8 ft) 2 = 5.5 ft
C. Volume
____________ ft 2x ____________ ft =
____________ ft 3
(surface area) (average depth) (volume)
Volume = 512 ft 2 x 5.5 ft = 2,816 ft 3
Next, multiply the pools volume in ft3 by
7.5 to get the pool capacity in gallons:
D. Pool Capacity
____________ ft 3 x 7.5 gallons/ft 3 =
____________ gallons
(volume) (pool capacity)
Pool Capacity = 2,816 ft 3. x 7.5 gallons/ft
3 = 21,120 gallons
Some of the more common pool sizes are:
Above-Ground Size Gallons*
15 ft Round 5,293
18 ft Round 7,622
21 ft Round 10,374
24 ft Round 13,550
12 ft x 24 ft Rectangle 8,626
27 ft Round 17,149
*Average Depth: 4 ft
In-Ground Size Gallons*
12 ft x 24 ft Rectangle 11,861
16 ft x 32 ft Rectangle 21,086
18 ft x 36 ft Rectangle 26,687
20 ft x 40 ft Rectangle 32,947
*Average Depth: 5.5 ft
2. Flow Rate
While the actual flow rate of a pump is
based on the total resistance of the system
as described below, the desired flow rate
must be calculated to verify it will satisfy
Turnover Rate and Water Velocity
requirements.
2A. Turnover Rate
The turnover rate for a swimming pool is the
amount of time required to circulate
the entire volume of water through the
system once to meet reasonably clean,
safe water standards. The minimum
recommended turnover rate is twelve (12)
hours, however an eight (8) to ten (10) hour
rate is quite common. Check with local
regulations for the minimum required
turnover rate.
Based on the pools capacity and the desired
turnover rate, the minimum rate at
which the water must be circulated in
Gallons Per Minute (GPM) is calculated
as follows:
A. Minimum Flow in Gallons per Hour (GPH)
____________ gallons ____________ hours =
____________ GPH
(pool capacity) (desired turnover rate)
(minimum flow,gallons per hour)
Minimum Flow: 21,120 gallons 10 hours =
2,112 gallons per hour
B. Minimum Flow in Gallons per Hour (GPM)
____________ gallons per hour 60 minutes
per hour = ____________ GPM
(minimum flow (minimum flow,
gallons per hour) gallons per minute)
Minimum Flow: 2,112 gallons per hour 60
minutes per hour =
35 gallons per minute
2B. Water Velocity
The maximum recommended water velocity is
six (6) or eight (8) feet per
second for suction lines and ten (10) feet
per second for return lines. Check
with local regulations for the maximum water
velocity for suction and return
lines. The table below lists the maximum
flow in GPM based on plumbing size
and water velocity.
Pipe Size Maximum Flow
(in) 6.0 ft/sec 8.0 ft/sec 10.0 ft/sec
1 1⁄2"" 38 GPM 51 GPM 63 GPM
2"" 63 GPM 84 GPM 105 GPM
2 1⁄2"" 90 GPM 119 GPM 149 GPM
3"" 138 GPM 184 GPM 230 GPM
Maximum Flow: 2"" suction side plumbing at
6.0 ft/sec = 63 gallons per minute
2C. Desired Flow
The desired flow rate must be between the
minimum flow based on the
Turnover Rate and the maximum flow based on
the Water Velocity. Note that
if higher flow rates are needed, such as for
water features, the maximum
possible flow would have to be increased by
using larger size plumbing
(e.g. increase from 2"" to 2 "" plumbing).
It is recommended to select a flow that is
higher than the minimum to
account for decrease in flow that naturally
occurs as the filter is loaded
with dirt and debris.
Minimum Flow (Turnover Rate): 35 GPM
Maximum Flow (Water Velocity): 63 GPM
Desired Flow: 50 GPM
Hydraulics
THE BASICS OF PUMP/FILTER SIZING
P u m p s
HAYWARD 17
Hydraulics
THE BASICS OF PUMP/FILTER SIZING
P u m p s
18 HAYWARD
3. Friction Loss
Everything that the water must pass through
within the circulation system
plumbing and equipment creates resistance,
or Friction Loss. The friction loss
for standard plumbing supplies such as pipe,
elbows, fittings, etc. can be found
using published reference tables. Friction
loss for equipment such as filters,
heaters, and chlorination systems can be
found in charts and/or curves provided
by the manufacturer. The sum of all the
resistance is called Total Dynamic Head
(TDH) and is typically measured in Feet of
Water or Feet of Head.
A properly sized pump will have the ability
to overcome the Total Dynamic Head
of the system while, at the same time,
providing flow that will satisfy Turnover
Rate and Water Velocity requirements.
For new installations, it is possible to
calculate TDH very accurately by using
reference tables and manufacturers data to
determine the friction loss asso -
ciated with every component in the
circulation system.
For existing installations, we are often
unable to determine the total amount of
pipe and fittings its underground.
Therefore, what follows is a simplified
rule-of-thumb means of determining Total
Dynamic Head.
We will need to add the resistance from the
vacuum (suction) side of the existing
pump to the resistance of the pressure side
of the pump. Note this assumes
the Static Suction Lift (i.e. vertical
distance from the center of the pumps
impeller to the surface of the water) is
offset by the water returning to the pool.
A. Friction Loss (Vacuum)
_________inches of mercury x 1.13 ft of
water = _________ft of water
(vacuum reading) (total resistance, vacuum)
Typically, however, a vacuum reading will
not be available, therefore, the table
below provides Common Head Loss Factors for
todays high-efficiency pumps.
Pump Size Head Loss Factor*
3/4 HP 4.5 to 5.5 ft of water
1 HP 7 to 9 ft of water
1 1/2 HP 10 to 12.5 ft of water
2 HP 13.5 to 16 ft of water
*Assumes 2"" suction line, not to exceed 40
ft long, minimal fittings, one (1) 2"" valve
and full-rated pumps.
Total Resistance (Vacuum): 9 ft of water
(existing 1 HP pump)
B. Friction Loss (Pressure)
____________ PSI x 2.31 ft of water / PSI =
____________ft of water
(filter pressure, clean) (total resistance,
pressure)
Total Resistance (Pressure): 10 PSI x 2.31
ft of water / PSI = 23 ft of water
C. Total Dynamic Head
__________ ft of water + __________ ft of
water = __________ft of water
(total resistance, vacuum) (total
resistance, pressure) (total dynamic head)
Total Dynamic Head: 9 ft of water + 23 ft of
water = 32 ft of water
4. Pump Sizing
We now have all the information necessary to
select the proper size pump
and/or filter and then proceed based on new
vs. aftermarket installations.
A pumps performance data is provided in GPM
(output) vs. Feet of Head
(resistance). The specific performance data
for Hayward pumps can be found
in the Pump Section, pages 7-16.
4A. Pump Sizing, New Installations
For new installations, use the desired flow
rate and Total Dynamic Head
calculated from tables and manufacturers
data:
Desired Flow ____________ GPM
Total Dynamic Head ____________ ft of water
Using Hayward Pump Performance Curves or
Tables, identify which pumps
performance comes closest to matching the
point where the Desired Flow
intersects with the Total Dynamic Head.
Desired Flow: 50 GPM
Total Dynamic Head: 32 ft of water (assume
to be the same as
determined above)
4B. Pump Sizing, Existing Installations
For existing installations, use the Total
Dynamic Head calculated from the
Friction Loss on the Vacuum and Pressure
side of the pump.
Total Dynamic Head ____________ ft of water
Using the manufacturers performance curve
for the existing pump, find the
flow that corresponds to the Total Dynamic
Head. This is the actual flow at
which the pump is currently operating, which
may or may not meet Turnover
Rate and Water Velocity requirements. Verify
the actual flow rate is between
the minimum flow based on the Turnover Rate
and the maximum flow based
on the Water Velocity.
Total Dynamic Head: 32 ft of water (assume
to be the same as
determined above)
If the actual flow rate does not meet the
Turnover Rate and Water Velocity
requirements, you must either modify the
system to add or remove restrictions
(e.g. use less restrictive plumbing fittings
and/or equipment) or vary the flow by
changing size of the pump.
If you increase or decrease your flow for
any reason, your resistance will
increase or decrease respectively. You
cannot read horizontally across
the curve at the same Total Dynamic Head to
choose another pump.
You must create a system curve based on the
following relationship:
_________ft of water x (______ GPM
______GPM)2 = ______ft of water
(current friction loss) (new flow rate)
(current flow rate) (new friction loss)
Choose the minimum and maximum flow rates
based on Turnover Rate and
Water Velocity and calculate the
corresponding friction loss using the
formula
above. Plot each combination of friction
loss and flow to create the system curve.
Current Flow: 70 GPM
Current Friction Loss: 32 ft of water
New Flow Rate (per Turnover Rate) = 35 GPM
New Friction Loss = (32 ft of water) x (35
GPM 70 GPM) 2 = 8 ft of water
New Flow Rate (per Water Velocity) = 63 GPM
New Friction Loss = (32 ft of water) x (63
GPM 70 GPM) 2 = 26 ft of water
The point where the performance curve for a
particular pump intersects the system
curve determines the flow and Total Dynamic
Head where that pump will operate.
Saving Money by Saving Energy
Depending upon utility rates, pool
characteristics, and equipment selected,
it is possible to recoup the premium cost of
an upgrade from a standard pump
to an energy efficient pump in the first
year of operation.
For example, a system featuring an energy
efficient high performance pump
drawing 5.34 amps at 230 volts where the
local utility rate is $0.12 per kWh
will cost you approximately $1.78 over a 12
hour period per day. A standard
pump drawing 7.0 amps will cost you
approximately $2.32 per day or an
extra $197 annually!
Use this worksheet to help determine your
energy savings:
A. Motor Amp Rating A
B. Voltage (e.g. 115 volts or 230 volts) B
C. Local Energy Rate ($ per kWh) * C
D. Approximate Power Usage (Watts) = A x B D
E. Kilowatts = D / 1000 E
F. $ per hour = E x C F
G. Hours of Operation G
H. Cost per Day = F x G H
J. Monthly Cost = H x 30 J
K. Yearly Cost = H x 365 K
*Refer to your utility bill to determine
locate rate
4B. Filter Sizing
A filter, be it DE, sand, or cartridge, has
a Design Flow Rate in GPM as
well as a Turnover Capacity in Gallons. See
the table below, for example.
The specific performance data for Hayward
filters is provided in the
Filter Section, pages 20-35.
Select a filter that meets or exceeds the
desired flow rate and turnover
capacity in gallons.
Model Effective Design Flow Turnover
Capacity
Number Filtration Rate (Gallons)
Area 8 Hours 10 Hours
S180T 1.75 ft 2 35 GPM 16,800 21,000
S210T 2.20 ft 2 44 GPM 21,120 26,400
S220T 2.64 ft 2 52 GPM 24,960 31,200
S244T 3.14 ft 2 62 GPM 29,760 37,200
S270T 3.70 ft 2 74 GPM 35,520 44,400
S310T 4.91 ft 2 98 GPM 47,040 58,800
S360SX 6.50 ft 2 131 GPM 62,400 78,000
Desired Flow: 50 GPM
Turnover 21,120 gallons in 10 hours
Select S220T (minimum)
One additional factor to consider in filter
sizing is bather load. Busier pools
require larger filters. Also, larger filters
provide longer cycles, reducing
everyday maintenance required by the
consumer during the pool season.
Summary
Using the information calculated above, you
can properly size the pump,
filter, and corresponding equipment,
assuring you meet Turnover Rate and
Water Velocity requirements while
eliminating the electrical waste and
potential damage to other system components
associated with a needlessly
oversized pump.
Hydraulics
THE BASICS OF PUMP/FILTER SIZING
P u m p s
HAYWARD 19
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